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∆ABC is a right angled triangle with AB = 6 cm, AC = 8 cm, ∠BAC = 90°. Then the radius of the incircle is
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- 4 cm.
- 2 cm.
- 6 cm.
- 3 cm.
- 4 cm.
Correct Option: B
As per the given in question , we draw a figure right-angled triangle BAC
Given , AB = 6 cm, AC = 8 cm , ∠BAC = 90°
From ∆ ABC,
BC = √AB² + AC²
BC = √6² + 8²
BC = √36 + 64
BC = √100 = 10 cm.
∴ Semi–perimeter of ∆ ABC = s = | = | = 12 cm. | ||
2 | 2 |
Area of ∆ ABC = | × AC × AB = | × 8 × 6 = 24 Sq. cm. | ||
2 | 2 |
∴ In-radius = | = | = 2cm. | ||
s | 12 |