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					 ⊥A of ∆ ABC is a right angle. AD is perpendicular on BC. If BC = 14 cm and BD = 5 cm, then measure of AD is :
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                        - 2√5cm.
- √5 cm.
- 3√5 cm.
- 3.5√5 cm.
 
Correct Option: C

In ∆ ABC and ∆ DAC, 
∠ADC = ∠BAC  , ∠C = ∠C 
By AA – similarity criterion, 
∆ ABC ~ ∆ DAC
| ∴ | = | = | |||
| DA | AC | DC | 
| ⇒ | = | ||
| CA | CD | 
⇒ CA² = CB × CD
= BC (BC – BD)
= 14 × (14 – 5) = 14 × 9
= 126 sq. cm.
∴ From ∆ ADC
CA² = AD² + C’D²
⇒ 126 = AD² + 9²
⇒ AD² = 126 – 81 = 45
⇒ AD = √45 = 3√5cm.
 
	