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⊥A of ∆ ABC is a right angle. AD is perpendicular on BC. If BC = 14 cm and BD = 5 cm, then measure of AD is :
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- 2√5cm.
- √5 cm.
- 3√5 cm.
- 3.5√5 cm.
Correct Option: C
In ∆ ABC and ∆ DAC,
∠ADC = ∠BAC , ∠C = ∠C
By AA – similarity criterion,
∆ ABC ~ ∆ DAC
∴ | = | = | |||
DA | AC | DC |
⇒ | = | ||
CA | CD |
⇒ CA² = CB × CD
= BC (BC – BD)
= 14 × (14 – 5) = 14 × 9
= 126 sq. cm.
∴ From ∆ ADC
CA² = AD² + C’D²
⇒ 126 = AD² + 9²
⇒ AD² = 126 – 81 = 45
⇒ AD = √45 = 3√5cm.