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In ∆ ABC and ∆ DEF, AB = DE and BC = EF. Then one can infer that ∆ ABC ≅ ∆ DEF, when
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- ∠BAC = ∠EDF
- ∠ACB = ∠EDF
- ∠ACB = ∠DFE
- ∠ABC = ∠DEF
- ∠BAC = ∠EDF
Correct Option: D
According to question , we draw figures of two similar triangles ABC and DEF
Two triangles are congruent if two sides and the included angle of one are equal to the corresponding sides and the included angle of the other triangle.
This is called SAS criterion .
