For a triangle ABC, D and E are two points on AB and AC

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For a triangle ABC, D and E are two points on AB and AC such that AD = ( 1 / 4 )AB, AE = ( 1 / 4 )AC. If BC = 12 cm, then DE is

As per the given in question , we draw a figure triangle ABC in which D and E are two points on AB and AC ,

Given that , AD =	1	AB
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AE =	1	AC and BC = 12 cm
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	AD	=	AB
	AE		AC

∆ ADE ~ ∆ ABC

∴ DE =	1	BC
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DE =	1	× 12 = 3 cm.
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