-
Q is a point in the interior of a rectangle ABCD. If QA = 3 cm, QB = 4 cm and QC = 5 cm, then the length of QD (in cm) is
-
- 3√2
- 5√2
- √34
- √41
Correct Option: A
According to question , we draw a figure of rectangle ABCD
Given that , QA = 3 cm, QB = 4 cm and QC = 5 cm,
Using Pythagoras theorem,
QD² + QB² = QA² + QC²
⇒ QD² + 16 = 9 + 25
⇒ QD² = 34 – 16 = 18
⇒ QD = √18 = 3√2 cm
