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					 ABCD is a cyclic trapezium whose sides AD and BC are parallel to each other. If ∠ABC = 72°, then the measure of the ∠BCD is
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                        -  162° 
 
-  18° 
 
-  108° 
 
- 72°
 
-  162° 
Correct Option: D
On the basis of question we draw a figure of cyclic trapezium ABCD whose sides AD and BC are parallel to each other ,
∠ABC + ∠CDA = 180° 
⇒ ∠CDA = 180° – 72° = 108°
AD || BC 
∠BCD = ∠ADE = ∠ABC = 72°
 
	