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ABCD is a cyclic trapezium whose sides AD and BC are parallel to each other. If ∠ABC = 72°, then the measure of the ∠BCD is
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- 162°
- 18°
- 108°
- 72°
- 162°
Correct Option: D
On the basis of question we draw a figure of cyclic trapezium ABCD whose sides AD and BC are parallel to each other ,
∠ABC + ∠CDA = 180°
⇒ ∠CDA = 180° – 72° = 108°
AD || BC
∠BCD = ∠ADE = ∠ABC = 72°