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					 ABCD is a cyclic quadrilateral. The side AB is extended to E in such a way that BE = BC. If ∠ADC = 70°, ∠BAD = 95°, then ∠DCE is equal to
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                        -  140° 
 
-  120° 
 
-  165° 
 
- 110°
 
-  140° 
Correct Option: A
According to question , we draw a figure of cyclic quadrilateral ABCD in which side AB is extended to E in such a way that BE = BC  , 
In concyclic quadrilateral ABCD, 
∠ADC + ∠ABC = 180° 
⇒ 70° + ∠ ABC = 180° 
∴ ∠ ABC = 180° – 70° = 110° 
∴ ∠CBE = 180° – 110° = 70° 
BC = BE
| ∴ ∠ BCE = ∠ BEC = | = 55° | |
| 2 | 
∠ BAD = 95°
∴ ∠ BAD + ∠ BCD = 180°
⇒ ∠ BCD = 180° – 95° = 85°
∴ ∠ DCE = ∠ BCD + ∠ BCE
∠ DCE = 85° + 55°= 140°
 
	