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ABCD is a cyclic trapezium in which AD || BC. If ∠ABC = 70°, then ∠BCD is
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- 110°
- 80°
- 70°
- 90 °
- 110°
Correct Option: C
As per the given in question , we draw a figure cyclic trapezium ABCD
As we know that the sum of the opposite angles of a concyclic quadrilateral is 180°.
∴ ∠ABC + ∠ADC = 180°
⇒ 70° + ∠ADC = 180°
⇒ ∠ADC = 180° – 70° = 110°
∵ AD || BC
∴ ∠ADC + ∠BCD = 180°
⇒ 110° + ∠BCD = 180°
⇒ ∠BCD = 180° – 110° = 70°.