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Two equal circles of radius 4 cm intersect each other such that each passes through the centre of the other. The length of the common chord is :
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- 2√3 cm
- 4√3 cm
- 2√2 cm
- 8 cm
- 2√3 cm
Correct Option: B
According to question , we draw a figure of two equal circles of radius 4 cm intersect each other such that each passes through the centre of the other ,
OC = 2cm
OA = 4cm
∴ AC = √OA² - OC²
∴ AC = √4² - 2² = √16 - 4
AC = √12 = 2√3
∴ AB = 4√3cm