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The distance between two parallel chords of length 8 cm each in a circle of diameter 10 cm is
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- 6 cm
- 7 cm
- 8 cm
- 5·5 cm
- 6 cm
Correct Option: A
As per the given in question , we draw a figure circle 
Given , Diameter = 10 cm
AB = CD
OP = OQ
From ∆ OAP,
OP = √OA² - AP²
OP = √5² - 4²
OP = √25 - 16
OP = √9 = 3 cm.
∴ QP = 2 × OP = 6 cm.
