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AB and CD are two parallel chords on the opposite sides of the centre of the circle. If AB = 10 cm, CD = 24 cm and the radius of the circle is 13 cm, the distance between the chords is
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- 17 cm
- 15 cm
- 16 cm
- 18 cm
- 17 cm
Correct Option: A
According to question , we draw a figure of a circle with two parallel opposite chords AB and AC , 
OE ⊥ AB and OF ⊥ CD
AE = EB = 5 cm
CF = FD = 12 cm
AO = OC = 13 cm
From ∆ AOE,
OE = √13² - 5² = √169 - 25
OE = √144 = 12 cm
From ∆ COF,
OF = √13² - 12² = √25 = 5 cm
∴ EF = OE + OF = 17 cm
