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A chord AB of a circle C1 of radius (√3 + 1)cm touches a circle C2 which is concentric to C1. If the radius of C2 is (√3 - 1)cm., the length of AB is :
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- 24√3 cm
- 8√3 cm
- 44√3 cm
- 4√cm
- 24√3 cm
Correct Option: C
According to question , we draw a figure of two concentric circles with centre O , 
Given , OC = √3 - 1
and OA = √3 + 1
From ∆ AOC
AC = √OC² + OA²
AC = √(√3 + 1)² - (√3 - 1)²
AC = √4√3 = 2. 4√3
∴ AB = 2AC = 4. 4√3 cm
