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AB is the chord of a circle with centre O and DOC is a line segment originating from a point D on the circle and intersecting AB produced at C such that BC = OD. If ∠BCD = 20°, then ∠AOD=?
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- 20°
- 30°
- 40°
- 60°
- 20°
Correct Option: C
On the basis of question we draw a figure of a circle with centre O and AB is the chord ,
Given , BC = DO = OA
∠DAB = 90°
∠DOA = 2 × ∠DCA
or 2 ∠BCD = 40°