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Each of the circles of equal radii with centres A and B pass through the centre of one another circle they cut at C and D then ∠DBC is equal to
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- 60°
- 100°
- 120°
- 140°
- 60°
Correct Option: C
As per the given in question , we draw a figure two circles equal radii with centres A and B ,
In ∆ ABD,
AD = BD = AB = radius
In ∆ ACB,
AC = CB = AB = radius
∴ ∠DBC = 60° + 60° = 120°