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Two chords AB and CD of a circle with centre O, intersect each other at P. If ∠AOD = 100° and ∠BOC = 70°, then the value of ∠APC is
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- 80°
- 75°
- 85°
- 95°
- 80°
Correct Option: D
On the basis of question we draw a figure of a circle with centre O , 
Given , ∠AOD = 100°
We know that the angle subtended at the centre is twice to that of angle at the circumference by the same arc .
| ∴ ∠ACD = ∠ACP = | = 50° | |
| 2 |
Again, ∠BOC = 70°
| ∴ ∠BAC = | = 35° = ∠PAC | |
| 2 |
∴ ∠APC = 180° – 50° – 35° = 95°
