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Chords AC and BD of a circle with centre O intersect at right angles at E. If ∠OAB = 25°, then the value of ∠EBC is
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- 30°
- 25°
- 20°
- 15°
- 30°
Correct Option: B
According to question , we draw a figure of a circle with centre O , 
From figure , OA = OB = radii
∠OAB = ∠OBA = 25°
∴ ∠AOB = 180° – 50° = 130°
| ∴ ∠BCA = | = 65° | |
| 2 |
∴ ∠EBC = 90° – 65° = 25°
