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Two circles C1 and C2 touch each other internally at P. Two lines PCA and PDB meet the circles C1 in C, D and C2 in A, B respectively. If ∠BDC = 120°, then the value of ∠ABP is equal to
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- 60°
- 80°
- 100°
- 120°
- 60°
Correct Option: A
On the basis of question we draw a figure of two circles C1 and C2 touch each other internally at P , 
Given , ∠BDC = 120°
∴ ∠CDP = 180° – 120° = 60°
CD || AB
∴ ∠ABP = 60° = ∠CDP
