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In a circle with centre at O (0, 0) and radius 5 cm, AB is a chord of length 8 cm. If OM is perpendicular to AB, then the length of OM is:
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- 2.5 cm.
- 3 cm.
- 4 cm.
- 1 cm.
- 2.5 cm.
Correct Option: B
On the basis of question we draw a figure of a circle with centre O ,
Given , AB = 8 cm
AM = MB = 4 cm
OA = 5 cm
From ∆ AOM ,
∴ OM = √OA² - AM²
OM = √5² - 4²
OM = √25 - 16
OM = √9 = 3 cm