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					 In a circle with centre at O (0, 0) and radius 5 cm, AB is a chord of length 8 cm. If OM is perpendicular to AB, then the length of OM is:
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                        -  2.5 cm. 
 
-  3 cm. 
 
-  4 cm. 
 
- 1 cm.
 
-  2.5 cm. 
Correct Option: B
On the basis of question we draw a figure of a circle with centre O ,
Given , AB = 8 cm 
AM = MB = 4 cm 
OA = 5 cm 
From ∆ AOM , 
∴ OM = √OA² - AM² 
OM = √5² - 4²
OM = √25 - 16 
OM = √9 = 3 cm
 
	