In the figure ∆ABC is inscribed in a circle with centre

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In the figure ∆ABC is inscribed in a circle with centre O. If∠ABC = 30° then ∠ACB is equal to

According to given figure in question ,

The angle of a semi–circle is right angle.
∴ ∠BAC = 90°
∴ ∠ACB = 90° – ∠ABC
∠ACB = 90° – 30° = 60°