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AB is a chord to a circle and PAT is the tangent to the circle at A. If ∠BAT = 75° and ∠BAC = 45°, C being a point on the circle, then ∠ABC is equal to
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- 40°
- 45°
- 60°
- 70°
- 40°
Correct Option: C
On the basis of question we draw a figure of a circle with centre O , 
If a line touches a circle and from the point of contact a chord is drawn, the angles which this chord makes with the given line are equal respe ctively to the angles formed in the corresponding alternate segments.
∴ ∠ACB = ∠BAT = 75° and ∠BAC = 45°
∠ABC = 180° – 45° – 75°= 60°
