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Two circles touch each other externally at point A and PQ is a direct common tangent which touches the circles at P and Q respectively. Then ∠PAQ =
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- 45°
- 90°
- 80°
- 100°
- 45°
Correct Option: B
According to question , we draw a figure of two circles touch each other externally at point A and PQ is a direct common tangent ,
AO is perpendicular to PQ.
OA = OP = OQ.
⇒ ∠OPA = ∠OAP = ∠OQA = ∠OAQ = 45°
∴ ∠PAQ = 90°
