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Two circles touch each other externally at P. AB is a direct common tangent to the two circles, A and B are point of contact and ∠ PAB = 35°. Then ∠ ABP is
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- 35°
- 55°
- 65°
- 75°
- 35°
Correct Option: B
As per the given in question , we draw a figure of two circles touch each other externally at P ,
OA = OP
⇒ ∠PAB = ∠OPA = 35°
∴ ∠AOP = 110° ⇒ ∠POB = 70°
∴ ∠ABP = | = | = 55° | ||
2 | 2 |