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From a point P, two tangents PA and PB are drawn to a circle with centre O. If OP is equal to diameter of the circle, then ∠APB is
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- 45°
- 90°
- 30°
- 60°
- 45°
Correct Option: D
As per the given in question , we draw a figure of a circle in which two tangents PA and PB are drawn to with centre O ,
Let OA = OB = r and OP = 2r
⇒ AP = PB
sin ∠APO = | = | = | |||
OP | 2r | 2 |
∠ APO = 30°
∴ ∠ APB = 60°