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					 In a circle with centre O, AB is a chord, and AP is a tangent to the circle. If ∠AOB = 140°, then the measure of ∠PAB is
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                        -  35° 
 
-  55° 
 
-  70° 
 
- 75°
 
-  35° 
Correct Option: C
According to question , we draw a figure of a circle with centre O , 
In ∆ OAB, 
Here , OA = OB = radius 
∴ ∠OAB = ∠OBA 
∴ ∠OAB + ∠OBA + ∠AOB = 180°
∴ 2∠OAB = 180° – 140° = 40°
| ⇒ ∠OAB = | = 20° | |
| 2 | 
∴ ∠PAO = 90°
∴ ∠PAB = 90° – 20° = 70°
 
	