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In a circle with centre O, AB is a chord, and AP is a tangent to the circle. If ∠AOB = 140°, then the measure of ∠PAB is
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- 35°
- 55°
- 70°
- 75°
- 35°
Correct Option: C
According to question , we draw a figure of a circle with centre O ,
In ∆ OAB,
Here , OA = OB = radius
∴ ∠OAB = ∠OBA
∴ ∠OAB + ∠OBA + ∠AOB = 180°
∴ 2∠OAB = 180° – 140° = 40°
⇒ ∠OAB = | = 20° | |
2 |
∴ ∠PAO = 90°
∴ ∠PAB = 90° – 20° = 70°