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O is the centre of a circle and AB is the tangent to it touching at B. If OB = 3 cm. and OA = 5 cm, then the measure of AB in cm is
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- √34
- 2
- 8
- 4
- √34
Correct Option: D
On the basis of question we draw a figure of a circle with centre O
Given that , OB = 3 cm. and OA = 5 cm
∠OBA = 90°
In ∆ OAB, OA² = OB² + AB²
⇒ 5² = 3² + AB²
⇒ AB² = 5² – 3² = 25 – 9 = 16
⇒ AB = √16 = 4 cm.
