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If PA and PB are tangents to the circle with centre O such that ∠APB = 50°, then∠OAB is equal to
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- 25°
- 30°
- 40°
- 50°
- 25°
Correct Option: A
As per the given in question , we draw a figure of circle with centre O in which PA and PB are tangents
PA = PB (tangents from an exterior point)
OA = OB = radii
Given , ∠APB = 50°
∠APO = ∠OPB = 25°
∠PAB = ∠PBA = | = 65° | |
2 |
∠OAP = 90°
∴ ∠OAB = 90° – 65° = 25°