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					 If PA and PB are tangents to the circle with centre O such that ∠APB = 50°, then∠OAB is equal to
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                        -  25° 
 
-  30° 
 
-  40° 
 
- 50°
 
-  25° 
Correct Option: A
As per the given in question , we draw a figure of circle with centre O in which PA and PB are tangents 
PA = PB (tangents from an exterior point) 
OA = OB = radii 
Given , ∠APB = 50°
∠APO = ∠OPB = 25°
| ∠PAB = ∠PBA = | = 65° | |
| 2 | 
∠OAP = 90°
∴ ∠OAB = 90° – 65° = 25°
 
	