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If PQ and PR be the two tangents to a circle with centre O such that ∠QPR = 120°, then ∠POQ is :
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- 90°
- 45°
- 30°
- 60°
- 90°
Correct Option: C
As per the given in question , we draw a figure of circle in which PQ and PR be the two tangents
PQ = PR (Tangents from the same exterior point)
Given , ∠QPR = 120°
∠OPQ = ∠OPR = | = 60° | |
2 |
∴ OQ ⊥ PQ (Tangent)
From ∆OQP ,
∴ ∠OQP = 90°
∴ ∠POQ + ∠OPQ = 90°
∴ ∠POQ = 90° – 60° = 30°