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AC is the diameter of a circumcircle of ∆ ABC. Chord ED is parallel to the diameter AC. If ∠CBE = 50°, then the measure of ∠DEC is
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- 50°
- 90°
- 60°
- 40°
- 50°
Correct Option: D
According to question , we draw a figure circle and chord ED is parallel to the diameter AC
∠CBE = 50°
∠BAC + ∠BCA = 90° [∵ ∠ABC = 90°]
∠ABE = 90° – 50° = 40°
∴ ∠ABE = ∠ACE = 40°
∴ ∠ACE = ∠DEC = 40°