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					 AC is the diameter of a circumcircle of ∆ ABC. Chord ED is parallel to the diameter AC. If ∠CBE = 50°, then the measure of ∠DEC is
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                        -   50° 
 
-   90° 
 
-   60° 
 
- 40°
 
-   50° 
Correct Option: D
According to question , we draw a figure circle and chord ED is parallel to the diameter AC
∠CBE = 50° 
∠BAC + ∠BCA = 90°  [∵ ∠ABC = 90°] 
∠ABE = 90° – 50° = 40° 
∴ ∠ABE = ∠ACE = 40° 
∴ ∠ACE = ∠DEC = 40°
 
	