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In ∆ ABC, the bisector of ∠BAC intersects BC at D and the circumcircle of ∆ ABC at E. If AB : AD = 3 : 5, then AE : AC is
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- 5 : 3
- 3 : 2
- 2 : 3
- 3 : 5
- 5 : 3
Correct Option: D
On the basis of question we draw a figure of a ∆ ABC in which the bisector of ∠BAC intersects BC at D and the circumcircle of ∆ ABC at E
Given that , AB : AD = 3 : 5
| = | ||
| AC | DC |
∠AEC = ∠CBA
∠BCE = ∠BAE
∠AEB = ∠ACB
∴ Ratio will be same.
