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If O is the circumcentre of a triangle ABC lying inside the triangle, then ∠OBC + ∠BAC is equal to
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- 90°
- 60°
- 110°
- 120°
- 90°
Correct Option: A
As per the given in question , we draw a figure of a triangle ABC and O is the circumcentre
In ∆ OBC ∵ OB = OC
∴ ∠ OBC = ∠OCB
∴ ∠ BOC = 180° – 2 ∠OBC
In ∆ OBD,
∠OBD = ∠ OBC = 90° – ∠BOD
Angle subtended by an arc at the centre is twice to that subtended at the circumference.
∴ ∠BAC = | ∠OBC | |
2 |
∠BAC = | (180° - 2∠OBC | |
2 |
∠BAC = 90° - ∠OBC
∴ ∠BAC + ∠OBC = 90°