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					 If O is the circumcentre of a triangle ABC lying inside the triangle, then ∠OBC + ∠BAC is equal to
 
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                        -  90° 
 
-  60° 
 
-  110° 
 
- 120°
 
-  90° 
Correct Option: A
As per the given in question , we draw a figure of a triangle ABC and O is the circumcentre 
In ∆ OBC ∵ OB = OC 
∴ ∠ OBC = ∠OCB 
∴ ∠ BOC = 180° – 2 ∠OBC 
In ∆ OBD, 
∠OBD = ∠ OBC = 90° – ∠BOD 
Angle subtended by an arc at the centre is twice to that subtended at the circumference.
| ∴ ∠BAC = | ∠OBC | |
| 2 | 
| ∠BAC = | (180° - 2∠OBC | |
| 2 | 
∠BAC = 90° - ∠OBC
∴ ∠BAC + ∠OBC = 90°
 
	