Point ‘O’ is the incentre of the ∆ PQR. If ∠POR

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Point ‘O’ is the incentre of the ∆ PQR. If ∠POR = 115°, then value of ∠PQR is :

1. 40°
2. 65°
3. 50°
4. 25°

Correct Option: C

According to question , we draw a figure of triangle PQR and Point ‘O’ is the incentre

Given , ∠POR = 115°
∴ ∠OPR + ∠ORP = 180° – 115° = 65°
∴ 2∠OPR + 2∠ORP = 130°
⇒ ∠QPR + ∠QRP = 130°
∴ ∠PQR = 180° – 130° = 50°