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Two chords AB, CD of a circle with centre O intersect each other at P. ∠ADP = 23° and ∠APC = 70°, then the ∠BCD is
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- 45°
- 47°
- 57°
- 67°
- 45°
Correct Option: B
On the basis of question we draw a figure of a circle with centre O
∠APC = 70° = ∠DPB
∴ ∠APD = 180° – 70° = 110° = ∠BPC
Also, ∠ADC = ∠ABC = 23°
∴ ∠BCD = 180° –110° – 23°= 47°
