- 
					 In the following figure, AB be diameter of a circle whose centre is O. If ∠AOE = 150°, ∠DAO = 51° then the measure of ∠CBE is : 
- 
                        -   115° 
 
-   110° 
 
-  105° 
 
- 120°
 
-   115° 
Correct Option: C
According to given figure in question ,
Given , ∠AOE = 150°, ∠DAO = 51° 
∴  ∠EOB + ∠AOE = 180° 
∠EOB = 180° – 150° = 30° 
OE = OB
∴ ∠OEB = ∠OBE = 150 ÷ 2 = 75° 
∴ ∠CBE = 180° – 75° = 105°
 
	