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In the following figure, AB be diameter of a circle whose centre is O. If ∠AOE = 150°, ∠DAO = 51° then the measure of ∠CBE is :
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- 115°
- 110°
- 105°
- 120°
- 115°
Correct Option: C
According to given figure in question ,
Given , ∠AOE = 150°, ∠DAO = 51°
∴ ∠EOB + ∠AOE = 180°
∠EOB = 180° – 150° = 30°
OE = OB
∴ ∠OEB = ∠OBE = 150 ÷ 2 = 75°
∴ ∠CBE = 180° – 75° = 105°