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In ∆ ABC, ∠A + ∠B = 145° and ∠C + 2∠B = 180°. State which one of the following relations is true ?
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- CA = AB
- CA < AB
- BC > AB
- CA > AB
- CA = AB
Correct Option: D
According to question , we draw a figure of a triangle ABC
Given , ∠A + ∠B = 145°
∠C = 180° – 145° = 35°
∠C + 2∠B = 180°
⇒ 2∠B = 180° – 35° = 145°
| ⇒ ∠B = | ||
| 2 |
⇒ 72.5° = ∠A
⇒ ∠B > ∠C
∴ AC > AB
