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All sides of a quadrilateral ABCD touch a circle. If AB = 6 cm, BC = 7.5 cm, CD = 3 cm, then DA is
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- 3.5 cm
- 4.5 cm
- 2.5 cm
- 1.5 cm
- 3.5 cm
Correct Option: D
As per the given in question , we draw a figure of quadrilateral ABCD and its all sides touch a circle 
Given , AB = 6 cm, BC = 7.5 cm, CD = 3 cm,
AE = AH
BE = BF
GC = FC
GD = HD
⇒ AE + BE + GC + GD = AH + BF + FC + HD
⇒ AB + CD = AD + BC
⇒ 6 + 3 = AD + 7.5
⇒ AD = 9 – 7.5 = 1.5 cm
