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					 In ∆ABC ∠A = ∠B = 60°, AC = √13 cm. The lines AD and BD intersect at D with ∠D= 90°. If DB = 2 cm, then the length of AD is
 
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                        -  3 cm 
 
-  3.5 cm 
 
-  4 cm 
 
- 4.7 cm
 
-  3 cm 
Correct Option: A
As per the given in question , we draw a figure of a triangle ABC
Here , ∠A = ∠B = ∠C = 60° 
BC = AB = AC = √13 cm 
BD = 2 cm 
In ∆ ABD, 
AB² = BD² + AD²
⇒ (√13)² = (2)² + AD² 
⇒ AD² = 13 – 4 = 9 
⇒ AD = √9 = 3 cm
 
	