Correct Option: B

Putting x = 0 in 4x + 5y = 40,
4 × 0 + 5y = 40 ⇒ 5y = 40

⇒ y =	40	= 8
	5

∴ Point of intersection on y-axis = (0, 8)
Again, putting y
= 0 in 4x + 5y = 40,
4x + 5 × 0 = 40 ⇒ 4x = 40

⇒ x =	40	= 10
	4

∴ Point of intersection on x-axis = (10, 0)
OA = 10 units
OD = 5 units = EC
∴ DA = 10 – 5 = 5 units
Again, OB = 8 units
OE = 4 units
BE = 8 – 4 = 4 units

∴ Area of ∆ADC =	1	× DA × DC =	1	× 5 × 4 = 10 sq. units
	2		2

∴ Area of ∆BEC =	1	× EC × BE =	1	× 5 × 4 = 10 sq. units
	2		2

∴ Required area = 10 + 10 = 20 sq. units.