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If ∠ A and ∠ B are complementary to each other, then the value of sec² A + sec² B – sec² A . sec² B is
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- 1
- - 1
- 2
- 0
Correct Option: D
A + B = 90°
⇒ B = 90° – A
∴ sec²A + sec²B – sec²A . sec²B
= sec²A + cosec²A – sec²A . cosec²A
| = | + | cos²A | sin²A |
| - | sin²A . cos²A |
| = | sin²A . cos²A |
| = | = 0 | sin²A . cos²A |
