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  1. If sec θ = x +
    1
    		(0° < θ < 90°), then sec θ + tan θ is equal to
    4x

    1. x
      2
    2. 2x
    3. x
    4. 1
      2x
Correct Option: B

sec θ =
4x² + 1
4x

tan θ = √sec² θ - 1
√[(4x² + 1 / 4x)²] - 1
√[(4x² + 1)² - (4x)² / (4x)²]
(2x + 1)(2x - 1)
=
4x² - 1
4x4x

∴ sec θ + tan θ =
4x² + 1
+
4x² - 1
4x4x

=
4x² + 1 + 4x² - 1
4x

=
8x²
= 2x
4x


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