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If A, B and C be the angles of a triangle, then put of the following, the incorrect relation is :
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sin A + B = cos C 2 2 -
cos A + B = sin C 2 2 -
tan A + B = sec C 2 2 -
cot A + B = tan C 2 2
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Correct Option: C
A + B + C = π
⇒ | = | - | 2 | 2 | 2 |
⇒ sin | ![]() | ![]() | |||
2 |
= sin | ![]() | π | - | C | ![]() | ||
2 | 2 |
= cos | 2 |
Similarly,
cos | ![]() | A + B | ![]() | = sin | C | |
2 | 2 |
cot | ![]() | A + B | ![]() | = tan | C | |
2 | 2 |
tan | ![]() | A + B | ![]() | = cot | C | |
2 | 2 |