If sin θ – cos θ = (7 / 13) and 0

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sin θ – cos θ =	7	......(i)
	13

sin θ + cos θ = x .....(ii)
On squaring both equations and adding,

2(sin²θ + cos²θ) =	49	+ x²
	169

⇒ x² = 2 -		49	=	338 - 49
		169		169

=		289	⇒ x =	17
		169		13