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  1. If
    sin θ + cos θ
    =
    5
    , the value of
    tan² θ + 1
    is
    sin θ - cos θ4tan² θ - 1
    1. 25
      16
    2. 41
      9
    3. 41
      40
    4. 40
      41
Correct Option: C

=
sin θ + cos θ
=
5
sin θ - cos θ4


tan θ + 1
=
5
tan θ - 14

⇒ 4 tanθ + 4 = 5 tanθ – 5
⇒ tanθ = 9
2tan θ
=
5 + 4
25 - 4

(By componendo and dividendo)
tan²θ + 1
=
(9)² + 1
=
81 + 1

tan²θ - 1(9)² - 181 - 1

=
82
=
41
8040



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