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From the top of a hill 200 m high, the angle of depression of the top and the bottom of a tower are observed to be 30° and 60°. The height of the tower is (in m) :
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400√3 3 -
166 2 3 -
133 1 3 - 200 √3
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Correct Option: C
AB = Hill = 200 metre
∠ADE = 30°
∠ACB = 60°
DE = BC = x metre
From ∆ABC,
| tan 60° = | BC |
| ⇒√3 = | x |
| ⇒ x = | metre | √3 |
From ∆AED
| tan 30° = | DE |
| ⇒ | = | √3 | (200 / √3) |
| ⇒ AE = | metre | 3 |
| ∴ CD = 200 – | = | 3 | 3 |
| = 133 | metre | 3 |
