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From the top of a light-house at a height 20 metres above sea-level, the angle of depression of a ship is 30°. The distance of the ship from the foot of the light house is
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- 20 m
- 20 √3 m
- 30 m
- 30 √3 m
Correct Option: B
AB = Height of light house = 20 metre
∠DAC = ∠ACB = 30°
In ∆ABC,
tan 30° = | BC |
⇒ | = | 20 | BC |
⇒ BC = 20√3 metre