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  1. The value of
    1. 4
    2. 1
    3. 3
    4. 2
Correct Option: D

(2 cos²θ – 1)

1 + tanθ+1 - tanθ
1 - tanθ1 + tanθ

= (2 cos²θ – 1)
(1 + tanθ)² + (1 - tanθ)²
1 - tan²θ

= (2 cos²θ – 1)

=
2sec² θ.cos² θ(2cos² θ - 1)
2cos² θ - 1

= 2


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