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					 If tan θ = 2, then the value of 8sinθ + 5cosθ is : sin3θ + 2cos3θ + 3 cosθ 
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                        -  21 5 
-  8 5 
 
-  7 5 
-  16 5 
 
 
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Correct Option: A
Expression
| = | sin3θ + 2cos3θ + 3cos θ | 
Dividing numerator and denominator by cos θ,
| = | tan θ . sin²θ + 2cos²θ + 3 | 
| = | 2sin² θ + 2cos²θ + 3 | 
| = | 2(sin² θ + 2cos²θ) + 3 | 
| = | = | 5 | 5 | 
 
	