If 7 sinα = 24 cos α; 0 < α

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If 7 sinα = 24 cos α; 0 < α < (π / 2) , then the value of 14 tan α – 75 cos α – 7 sec α is equal to

7 sin α = 24 cos α

⇒		sin α	=	24	⇒ tanα =	24
		cosα		7		7

∴ cosα =		1	=	7
		sec α		7

∴ 14 tanα – 75 cosα – 7 secα

= 14 ×		24	- 75 ×	7	- 7 ×	25
		7		25		7

= 48 – 21 – 25 = 2