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If tan θ – cot θ = 0 and θ is positive acute angle, then the value of
tan(θ + 15°) is tan(θ - 15°)
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- 3
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1 √3 -
1 3 - √3
Correct Option: A
tanθ – cotθ = 0
⇒ tanθ = cotθ
⇒ tanθ = tan (90° – θ)
⇒ θ = 90° – θ
⇒ 2θ = 90°
⇒ θ = 45°
| ∴ | tan(θ - 15°) |
| = | = | tan(45° - 15°) | tan 30° |
| = | = √3 × √3 = 3 | (1 / √3) |
