A ladder is placed along a wall such that its upper end

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A ladder is placed along a wall such that its upper end is touching the top of the wall. The foot of the ladder is 10 ft away from the wall and the ladder is making an angle of 60° with the ground. When a man starts climbing on it, it slips and now ladder makes an angle of 30° with ground. How much did the ladder slip from the top of the wall?

In ∠ABC,
AB = Wall
BC = 10 feet
∠ACB = 60°

∴ tan 60° =	AB
	BC

⇒ √3 =	AB
	10

⇒ AB = 10 √33 feet
∴ AC = √AB² + BC²

= √300 + 100
= √400 = 20 feet
Case II,
∠BDE = 30°

∴ sin 30° =	BE
	DE

⇒		1	=	BE
		2		20

⇒ BE = 10 feet
∴ AE = 10 √3 – 10
= 10 (√3 - 1) feet
= 10 (1.732 – 1)
= 10 × 0.732 = 7.32 feet