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					 If the angle of elevation of the sun decreases from 45° to 30°, then the length of the shadow of a pillar increases by 60m. The height of the pillar is
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                        - 60 (√3 + 1) metre
- 30 (√3 - 1) metre
- 30 (√3 + 1) metre
- 60 (√3 - 1) metre
 
Correct Option: C

AB = Height of pole = h metre
CD = 60 metre
In ∆ABC
| tan 45° = | ⇒ 1 = | BC | BC | 
⇒ BC = h metre
In ∆ABD,
| tan 30° = | BD | 
| ⇒ | = | √3 | h + 60 | 
⇒ √3 h = h + 60
⇒ √3 h – h = 60
⇒ h (√3 - 1) = 60
| ⇒ h = | √3 - 1 | 
| = | = | = 90 | (√3 - 1)(√3 + 1) | 2 | 
= 30 (√3 + 1) metre
 
	